Hide/Show Widgets from script

[p.behr]

Is it possible to show/hide a widget from a custom script?

let form = getWidget('theForm');
form.someProperty? = someValue?;
success();

[sean.lanktree]

Yes.

myWidget.show();
myWidget.hide();

In the next update, you will be able to do this by setting an app variable.

[p.behr]

Well that's easy :p
Thanks!!

[p.behr]

This works OK for a regular form, but I'm having issues with a pop-up form.
The hide() seems to clear out the form, but leaves the container(s):

img1.png

img2.png

[Johnny Major]

Here is an example script that will check if the widget is in a popup or not and act accordingly.

hideShowWidget takes two parameters

• widget
• action - hide/show

var myWidget       = getWidget('myChart'),
    hideShowWidget = function (wdg, action) {
        var popupContainer = wdg.up('widget-popup'),
            livesInPopup   = (!Valence.isEmpty(popupContainer)) ? true : false,
            actOn          = (livesInPopup) ? popupContainer : wdg;

        if (!Valence.isEmpty(actOn[action]) && typeof actOn[action] === 'function') {
            actOn[action]();
        }
    };

hideShowWidget(myWidget, 'hide');